# Maths question

1. Hahaha I so didnt read it as they had their own money to begin with..
That makes so much more sense that how I was was doing it! Toooo Clever leisylou!!

2. Originally Posted by CMF
Oh my gosh how did you dooooo that???
I haven't checked the answer with him but it certainly looks right!
Did you just guess random numbers or did you actually have a methodical way of working it out?
If I read the question correctly and it was hypothetical, not sequential (does that make sense?) there wasn't a proper method, I just kind of worked backwards :-)

For Alice to give away a quarter, hers had to be under \$25 as otherwise she would have started with \$100 and couldn't have gotten anything off Bill to make it up to the \$100. Claire's had to be divisible by 3 as she was giving away a third, and it couldn't be less than \$75 as she was getting a quarter of Alice's and hers was under \$25. So then I kind of worked the multiples of 3 between \$81 & \$90 for Claire and got to it that way...

3. Simultaneous equations?
So if a=amount Alice has, etc
Then the three statements equate to:
a+b/2=100
b+c/3=100
c+a/4=100

Rearrange and solve for a, b and c?

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Summer  (27-02-2015)

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Originally Posted by Leisylou
If I read the question correctly and it was hypothetical, not sequential (does that make sense?) there wasn't a proper method, I just kind of worked backwards :-)

For Alice to give away a quarter, hers had to be under \$25 as otherwise she would have started with \$100 and couldn't have gotten anything off Bill to make it up to the \$100. Claire's had to be divisible by 3 as she was giving away a third, and it couldn't be less than \$75 as she was getting a quarter of Alice's and hers was under \$25. So then I kind of worked the multiples of 3 between \$81 & \$90 for Claire and got to it that way...
Ermmmm.... ok..... lol.
Very well done LeisyLou!
I was playing around with numbers around what yours were, but just couldn't get there. I was trying to find a multiple of 3 and multiple of 4 etc but it just did my head in!

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Summer  (27-02-2015)

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Originally Posted by deku
Simultaneous equations?
So if a=amount Alice has, etc
Then the three statements equate to:
a+b/2=100
b+c/3=100
c+a/4=100

Rearrange and solve for a, b and c?
That's exactly what I had written down on my piece of paper, but then realised I don't know how to do simultaneous equations lol.

8. Originally Posted by CMF
That's exactly what I had written down on my piece of paper, but then realised I don't know how to do simultaneous equations lol.

2015-02-27 11.35.41.jpg

9. Originally Posted by Leisylou
For Alice to give away a quarter, hers had to be under \$25 as otherwise she would have started with \$100 and couldn't have gotten anything off Bill to make it up to the \$100. Claire's had to be divisible by 3 as she was giving away a third, and it couldn't be less than \$75 as she was getting a quarter of Alice's and hers was under \$25. So then I kind of worked the multiples of 3 between \$81 & \$90 for Claire and got to it that way...
That's very clever problem solving, I'm impressed!

Edit- i have no idea why this image keeps attaching to all my posts now, sorry!

10. Originally Posted by deku
Wow - that's awesome! SO impressed - that is pretty freaking amazing problem solving and if I knew how to do maths I'm sure it would make sense to me!!! Brilliant brain you have :-)

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Originally Posted by deku
Ok. I've been staring at this for the last 10 mins, and I'm a bit stumped lol. So I get the initial equations, and I get why you minused the 1/2b etc to the other side, but where did the a=400-4c come from? Why did you do that rather than just minus it like you did the first 2 equations?

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